Alexander Zverev secured his place in the French Open semi-finals for a fourth straight year after overcoming Alex de Minaur on Wednesday.

The world number four will meet Casper Ruud, who progressed with a bye after Novak Djokovic's injury withdrawal, in the last four after a battling 6-4 7-6 (7-5) 6-4 triumph on Court Philippe-Chatrier.

De Minaur overcame Daniil Medvedev in the previous round to earn his first Roland-Garros quarter-final appearance, though it was one to forget as his serving – and Zverev's grit – proved the 11th seed's undoing.

Both players traded a break apiece during an entertaining opening in the French capital, only for De Minaur's double fault to hand Zverev the 4-3 advantage to hold his serve and take the first set.

The Australian snatched a crucial break midway through the second set, yet Zverev – who was warned with a time violation by the umpire for taking too long over his serve – saved a set point to keep his hopes alive.

That was a sign of things to come, too, as Zverev once again fought from 4-0 and 5-1 down in the tie-breaker, somehow clinching a 2-0 lead in the match from a seeming point of no return.

Having failed to level in that cruel tie-break defeat, De Minaur managed to break Zverev late in the third set but the former responded immediately to secure a hard-fought win in just under three hours.

Data Debrief: Zverev continues on song

Zverev extended to 11 straight wins after this victory, with that run including his sixth ATP Masters 1000 title in Rome two weeks prior to the start of this major.

The German is just the 11th man of the Open Era to reach four consecutive semi-finals at the French Open, where a rested Ruud awaits next.

De Minaur, meanwhile, misses out on the chance to become the first Australian man since Pat Rafter in 1997 to make the last four on Parisian clay.